Anyone got an nth root algorithm?

[MWheatley]

I'd rather not reinvent the wheel, so if anyone cares to share one, I'd be grateful.

Malcolm

[bplus]

I'd rather not reinvent the wheel, so if anyone cares to share one, I'd be grateful.

Malcolm

r th root of n = n^(1/r) eg square root of 2 = 2 ^ (1/2) or 2 ^ .5

[Qwerkey]

Er, yes: somewhat obvious.  So were you actually asking for something else, Malcolm?  An algorithm sounds rather grand.

[MWheatley]

Alas, no, Qwerkey: it was a moment of mathematical blindness, I'm afraid.  Things ill-remembered from 50 years ago, etc.  And probably badly learned, then -- slide rules for university exams were still the norm in my day, at least in my undergraduate years.

So thank you, bplus.  Much appreciated.

Malcolm

[bplus]

Alas, no, Qwerkey: it was a moment of mathematical blindness, I'm afraid.  Things ill-remembered from 50 years ago, etc.  And probably badly learned, then -- slide rules for university exams were still the norm in my day, at least in my undergraduate years.

So thank you, bplus.  Much appreciated.

Malcolm

If it weren't for Basic coding, all my math lessons would be long gone.

Qwerkey, if you were hoping for an algorithm and don't remember my algorithm for power calculations (alas QB64 has it covered) I would be glad to share my discovery again :)

[MWheatley]

Bplus,

I don't know the algorithms to which you refer, but please feel free to share them anyway.  I'm interested!  And I still code in QB45 as well as QB64.

MDW1954

[bplus]

Bplus,

I don't know the algorithms to which you refer, but please feel free to share them anyway.  I'm interested!  And I still code in QB45 as well as QB64.

MDW1954

Hi MWheatley,

If you missed the conversation, it was here:
https://www.qb64.org/forum/index.php?topic=364.msg2439#msg2439

[MWheatley]

Thanks!

Malcolm